I've been looking for this one for ages, and the one I created based on an equation I found a little while ago didn't work too well :(

#### Investigation

Calculate distance, bearing and more between two Latitude/Longitude points shows lots of equations in math, and implemented in JavaScript. Chris Veness's page also contains an Excel formula of the ‘Haversine’ equation (actually, using the "spherical law of cosines") for distances between points in kilometres:

=ACOS(SIN(Lat1)*SIN(Lat2) +COS(Lat1)*COS(Lat2)*COS(Lon2-Lon1)) *6371

But it wasn't working, because my GPS points (Lat/Lon) were in decimal degrees, not radians. So I used the formula I found at Latitude And Longitude In Excel (under the "Great Circle Distances" section) by Chip Pearson:

=RadiusEarth*ACOS(COS(RADIANS(90-Lat1)) *COS(RADIANS(90-Lat2)) +SIN(RADIANS(90-Lat1)) *SIN(RADIANS(90-Lat2)) *COS(RADIANS(Long1-Long2)))

where Chip gives RadiusEarth as 6378.135 kilometres. This didn't match up with distances I had when calculated from other systems. But Chris's page has:

R = earth’s radius (mean radius = 6,371km)

Digging deeper, I found Chris's Vincenty formula for distance between two Latitude/Longitude points page which includes a table on different datum models (treating Earth as an ellipsoid), it shows WGS-84 & GRS-80 having the greatest radius on an ellipsoid as 6378.135km & the smallest as 6356.752km.

So Chip was using the maximum radius of the Earth, not the mean radius like Chris (I'm not sure where Chris gets the mean radius from). Substituting Chris's R for RadiusEarth in Chip's formula gives:

#### Solution

=ACOS(COS(RADIANS(90-Lat1)) *COS(RADIANS(90-Lat2)) +SIN(RADIANS(90-Lat1)) *SIN(RADIANS(90-Lat2)) *COS(RADIANS(Long1-Long2))) *6371

and my final version that uses Excel cell references is:

=ACOS(COS(RADIANS(90-A2)) *COS(RADIANS(90-A3)) +SIN(RADIANS(90-A2)) *SIN(RADIANS(90-A3)) *COS(RADIANS(B2-B3))) *6371

PS. To calculate distances in miles, substitute R (6371) with 3958.756 (and for nautical miles, use 3440.065).

## 342 comments:

1 – 200 of 342 Newer› Newest»You are the man. After much searching, your post gave me just the Excel formula I needed, with the correct distances (as measured at that moveable-type site)

I'm trying to visit every Larosas, Busken, Graeters and Skyline in Cincinnati in one day, and was trying to figure out distances

dan.

www.everywhatever.com

Simply... Thank you

Thanks so much, this is exactly what I was looking for.

Bless you.

Thank you- this, plus the batch calculator at www.batchgeocoder.com make for a powerful combination... Saved me loads of research!!!

Thank you!!!

You made my day!

Thanks a lot!

From a happy Norwegian

Thanks so much, it saved me hours.

I'm setting up mini-conferences around the country, and your formula made it easy to convert a database of zip code lat/lon figures into distances. Now I can sort cities instantly by distance from a point. Thanks! Mark Lee

Impressive ! Thanks a lot, I needed 15 minutes to tweak it the way I need instead of hours of copy/paste ! Thanks :))

Amazing! just what I was looking for!

Thanks for the information.

I am new to excel, could you give a sample file ?

how do i define the columns ?

thanks a million in advance

gabriel

I think the formula needs one more set of brackets around the latitude part of formula.

could you give an example

excel layout with the data typed?

input as google earth ?

gabriel

This is what I'm looking for, thanks.

Distance between two points with curvature of earth accounted for.

Thanks very much.

Thanks a million!!!

BluMM,

I need a variation on this. Given a set of coordinates, how do I calculate the coordinates one mile away at a given bearing? Any ideas?

Thanks a lot! You really really made my day. I was constructing a distance variable between households and health facility to use it in a service use prediction in stata. I spent time looking for a command i stata (i don't have a GIS soft)...the I found your formula). Thanks a million!

Absolutely wonderful!

Absolutely wonderful

Excellent, just excellent. Thanks very, very much.

Perfectamundo. I downloaded some Lat/Long data by zip code and imported it into my SQL database. I then tweaked your formula to be able to use it in Crystal Reports.

Wonderful. Thanks a lot. Could you please gave the other formula for calculating the angle between two coordinates.

Hello readers

This is very close to what I am looking for. However, I need a formula that does the job in another way, so to say :-)

Given:

Lon1, Lat1, radius, angle

looking for:

lon2, lat2

where do I land (lon2, lat2) with the above mentioned figures (under "given")?

Can anyone help me with this?

Best regards,

Ralph

that is so so frickin cool. thank you

This is the Bomb!!!

You've saved me so much effort - thanks!

Thank you..Very Simply

Alvaro...From Brasil/ São Paulo.

U be 'da man!!!

You are a life saver!

simply amazing..thx

Thank you very much. This is excellent!! Saved so much time. God bless you

You are a life saver.

Can anyone send me a working copy of the Vincenty formual in excel?

I've already got a basic formula / excel work book for calculating the distance between two airports (using their respective lat/longs read from separate table) but I'm no genius when it comes to tweeking the formula to accomodate the changes by Vincenty.

Any help greatly appreciated.

Regards,

Fergusflan@gmail.com

Finally found what I need.. thank you so much!!!

OMG, you are the master of the masterss.. it save me a lot of time and extra points with my boss.

This is AWESOME... though i'd love to see how to calculate travel-distance between 2 zip codes/2 lat/longitudes

Thanks a lot. Saved a lot of time.

Awesome ! Great formula and even better description.

Yep. thanks!

Thanks for creating a very useful tool! You made my day!

I cannot believe how simple you made this look! i sent hours looking at other formulas and when I tried to convert it it was always the wrong answer

It nice that the internet is used for such great resources and that people like are willing to share their wonderful skills

I cannot believe how simple you made this look! i sent hours looking at other formulas and when I tried to convert it it was always the wrong answer

It nice that the internet is used for such great resources and that people like are willing to share their wonderful skills

amazing!

You just saved me doing this manually 260 times. I owe you a MASSIVE beer.

this is great-can it be tweaked into Crystal?

Thanks for sharing this formula! There is just no way I could have figured this out on my own.

This is great. But how do I use it in Crystal?

Very helpful in the current project at work.

I did notice that the radius of earth noted does not match up with Google's. They appear to be using 3963.1676 mi as the earth's radius to calculate distance between locations in miles. I am using this radius in calculating my distances to coincide with Google's.

First Thanks in 2010. Thanks!

Hi,

Thank you for making this easy in excel,but how do you do it in crystal report? Please help.

Thanks.

I don't think this works between places that are separated by the prime meridian or the equator...or did I miss something?

Thanks a lot. Saved loads of effort

Fantastic! I am involved in tagging butterflies and was just settling down for a few hours reading to figure out how to do this when I found your answer presented on a silver platter!

Awesom!!!

... and that's why we love the web. Sharing knowledge.

Thank you. You saved me so SO much work.

Brilliant...simply brilliant...

Awesome

You need to be kissed.

I spent 2hrs on this yesterday and failed. With your help I spent 5 minutes today and it worked a treat. Many thanks!

Just wonderful! Thanks so much.

This helped me set up a database which calculated the closest branch to every telephone exchange in the country.

kick-ass man.

I was getting no where with co-ordinates in degrees, excel and the haversine formula until i found your page, after which my quest was complete. Many thanks.

Three years later and you're still being thanked! I have to thank you, too! This is incredible!!

Wow, I am very much in your debt. I tag rockfish and this task of calculing their movement was a mountain of a task. You have made it easy. Thank you very much.

Ditto what everyone else has ever said about your good character, name, intellect, the cut of your jib, etc, etc. THANK YOU!!!

Amazaing work.... Hats off mate

Amazing work.... Hats off mate

Finally. Been combing the internet for ages looking for something like this. I couldn't get any of the other formulas I tried to work

Thank you so much

Really great stuff! I did a lot of investigation with poor results before finding this. A big thanks for the knowledge and sharing it!!!

Thank you for posting this little piece of genius...

Marvellous....

Of course.. I now want to move to the next level... :)

My next search, and indeed work myself, is to try to get distances to travel by road, and not just as the crow flies.

I spent HOURS (2 working days) on searching for other formulas that wouldn't work. Yours worked in 2 minutes and saved the day.

This IS the best. Thanks a TON!!!

Perfect mate, cheers. Will vote up this result in the googles.

AWERSOME. Saved me a bunch of time to have this already done for me. Thank you!

Thanks for your post. It sounds like you're interested in making something like the highway mileage charts sometimes shown on paper maps, where you can find the distance between any two points that are included in the chart. Is that right? I don't believe that we have any such functionality in Google Maps right now, though that's an interesting feature suggestion, and I can pass it on to the relevant team.

As with so many others, this EXACTLY solved my problem, saving me hours and hours of time.

In the spirit of giving back, here are some sample row equations if you're trying to build a "Triple-A Road Atlas" of city-to-city distances.

This assumes a grid with city names across the top and left columns, Decimal Latitude in column B, and Decimal Longitude in column C.

Cell $B$28 is the arbitrary cell storing the planet's diameter (since that seems subject to debate).

Column D =ACOS(COS(RADIANS(90-$B$2)) *COS(RADIANS(90-B3)) +SIN(RADIANS(90-$B$2)) *SIN(RADIANS(90-B3)) *COS(RADIANS($C$2-C3))) *$B$28

Column E =ACOS(COS(RADIANS(90-$B$3)) *COS(RADIANS(90-B2)) +SIN(RADIANS(90-$B$3)) *SIN(RADIANS(90-B2)) *COS(RADIANS($C$3-C2))) *$B$28

Column F =ACOS(COS(RADIANS(90-$B$4)) *COS(RADIANS(90-B2)) +SIN(RADIANS(90-$B$4)) *SIN(RADIANS(90-B2)) *COS(RADIANS($C$4-C2))) *$B$28

Column G =ACOS(COS(RADIANS(90-$B$5)) *COS(RADIANS(90-B2)) +SIN(RADIANS(90-$B$5)) *SIN(RADIANS(90-B2)) *COS(RADIANS($C$5-C2))) *$B$28

Column H =ACOS(COS(RADIANS(90-$B$6)) *COS(RADIANS(90-B2)) +SIN(RADIANS(90-$B$6)) *SIN(RADIANS(90-B2)) *COS(RADIANS($C$6-C2))) *$B$28

Column I =ACOS(COS(RADIANS(90-$B$7)) *COS(RADIANS(90-B2)) +SIN(RADIANS(90-$B$7)) *SIN(RADIANS(90-B2)) *COS(RADIANS($C$7-C2))) *$B$28

Etcetera...

First paste the column formula into the topmost cell of the column, then copy that cell and paste it down the length of the column. I'm not a good enough Excel Maven to automate this into a single equation that can be pasted throughout the NxN city matrix

Thanks!

By the way, since the equations are unit-neutral, you can easily come up with separate distance tables in Miles and Kilometers by changing the value of the Radius from one to the other.

amazing!

pleas expalin what is in the cells A2, A3, B2 and B3.

Thanks Anthony fba@fbatm.biz

I should have read more. I now understand what A2 A3 B2 and B3 are and it works a treat. Please ignore mt query

I love you, Im totally i love with you ;-) Thanks

What format do you use to enter the lat/lon into Excel? Foe instance, what would 56°57′09.58″

look like in Excel?

Spent hours trying to make sense of other sites. Found yours, tweaked and had it doing exactly what I needed in minutes!

Thank you!

Is anyone else having troubles for areas in the south? I have verified that all of my coordinates are correct, but when I try to calculate a distance between 49512 and 33024 I only get 390 miles... It should be quite a bit more from Michigan to Florida!

Thanks a lot.

This is great. Is there a version that calculates bearing?

Thanks a lot! Any chance also for the formula to determine the direction/bearing/azimuth from Pt A to Pt B ?

Thanks a billion!

Good work! Many thanks from Wales!

This worked great! Thanks from Ontario!

thankyou thankyou....!

(to add to the million other thankyous on this comment page)

ha ha and I'm also from Wales like the guy above...

these Welsh fellas stick together! What are the chances of finding them like this???

Thanks Man. "CHOKRAN" :)

Thanks - you've made a long and complicated job simple. Brilliant.

Thanks from sunny Milton Keynes. Saved me a load of time

seriously, you are the man!!

Excellent!Thank you very much indeed for making it available to the rest of us.

AWESOME!!! I have spent hours trying to tweak the formula to work in Excel. Your post made it "copy/paste"! Thanks!

I'm putting the following coordinates, but it's not working:

A2: -23502253 B2: -47488436

A3: -23526376 B3: -47464113

Can someone please help me?

Thank you so much, this is exactly what i needed

Consider me the second happy Norwegian (at least) you've helped out!

Thank you. I needede to calculate about 1000 flights for my company's carbon footprint. Used a simpler formula that was quite good but slightly inaccurate, did for example return different results when switching the destinations around. Then I found your solution that does the job presisely and was also easy to put into VBA code. After recalculating the 1000 flights the difference was only 0,001% or 90 kg CO2 !! Whatever, always good to have the best methodology in use ! Will certainly look for more tips & tricks on your blog !

Thank you, wish I had found your site before all the other I looked up first !

Another happy Norwegian..

you are heaven-sent! :) thanks man.

does this formula work for 2 points on a bell curve ...i need to calculate the distance between to points on a bll curve?

thx

Thank you very much. By combining your formula and http://www.excelforum.com/excel-programming/537429-closest-neighbour-coordinates.html for coordinate lookup, I was able to do reverse geo coding withing excel. Great job.

Brilliant ... now I can easily compute the distance between the Volvo yachts racing around the world!

its coolest investigation!, but i just want know how about calculate bearing or azimuth?

great regard :)

engkin

eloknegerikuindonesia

Amazing. I applaud your hard-work and know how as im sure you dedicated a lot of time and energy to perfecting the fomrula. Comparing the distance from Toronto-Denver against geobytes, the formula was accurate within 3.75 miles; 99.8% accurate! Again, amazing. Endless thanks.

Genius. Thank you.

I looked at over 50 websites on this topic today - and this is the only one that was clear and made sense, thanks!

Awesome...

thank you very much. I've been racking my brain on this all day.

you are a genius among men.

From a smallish charity in Australia: CHEER'S MATE!!

Thanks for posting this blog .This was so much helpful and was time consuming for mines to calculate the question using your tips .

Thanks!... This formula gives distances in km?..

Thanks brother! This is exactly what I was looking for!

Thanks so so so so much buddy!! You are the man!!! You saved like a million person hours ;)

God bless you

Excellent work and very well presented! You are a credit to your species.

You should consider revisiting the Haversine equation because the Law of Cosines version that you're using is considered UNRELIABLE and NOT RECOMMENDED. See here for discussion.

The haversine formula for decimal degree coordinates in Excel is:

=2*asin(min(1,sqrt(sin((radians(lat2)-radians(lat1))/2)^2+cos(radians(lat1))*cos(radians(lat2))*sin((radians(lon2)-radians(lon1))/2))^2))*6371008.7714

6371008.7714 m (3958.761316 miles) is the mean radius of Earth as defined by the International Union of Geodesy and Geophysics (IUGG).

This haversine version will alwyas produce valid results. Your final equation produces "#NUM!" with, e.g., lat1: 41.89028, lon1: -87.75483, lat2: 41.89028, lon2: -87.75483.

Apologies, I could have simplified that just a bit:

=2*asin(min(1,sqrt(sin((radians(lat2-lat1))/2)^2+cos(radians(lat1))*cos(radians(lat2))*sin((radians(lon2-lon1))/2))^2))*6371008.7714

However, if we're going to worry about such a degree of false precision, all coordinates should really be converted from geodetic to geocentric before using any of these trigonometric equations.

Thanks. I was going to have to get on Google Earth and use the ruler tool to calculate distances from a central point to a number of weather stations that did have reported lat-long info. Your equation saved me a bunch of time.

How would I reference your work in a paper citation?

Thanks again,

Joe H

Thanks Mate....appreciate your generosity.

Fantastic, works a treat. Thank you.

if the lat long values are in degrees, then cant we convert it into radians and then apply haversine's formula?

Thank you so much. supper ...

Wow thank you man. I compares the results to google maps and its within the same proximities. Thank you thank you.

Damn, I keep getting the #NUM error and can't figure out what's wrong...

Damn, I keep getting the #NUM error and can't figure out what's wrong...

Is this the greater circle line distance formula that you are using?

is this the greater circle line distance formula that you are using

Thank you!

This part of the formula keeps giving me errors- *COS(RADIANS(B2-B3))

my longitude figures are all negative. I suspect that is the problem but unsure of what to do.

I am getting errors and I suspect it's with this part of the formula

*COS(RADIANS(B2-B3))

my longitude values are all negative. Do they need to be converted to positive to use? thanks

I copied it, pasted it, substituted my cell references for the lat long names, and I was done! It was too easy.

Thanks!

Steve

My longitude data is negative and causes this to bomb. Does it need to be made positive?

Thanks a lot, appreciate it very much :)

Suresh

Thanks a lot, it helped me.

-suresh

I'm pretty sure ppl will thank u 4ever, but I couldn't just use ur info and leave! so here is my THANK YOU as well!

THANKS!!!

Great! Thank you very much!

Awesome! I needed to get to feet but had to start somewhere! Just to continue from km to ft take result through =DistKm*3280.8

Thank you!

Thank you!

Holly ship! you made my day!

Thank you, thank you, thank you, thank you.

Like the others have said, you just saved me a ton of time (that I didn't have).

Cheers from Germany!

This is great - exactly what I was looking for.

Just wondering if anyone has been able to build a solution that can take a few hundred points and cluster them based on certain criteria example within 10km of each other?

thank you for your sharing.

I searched for this solution for YEARS.......almost no one has ever put this out to where the average non-mathematician guy can obtain and use it. Thank You.

This kind of math is DIFFICULT and not apparent to mere mortals.

Dude, this is awesome. Saved $59 purchase...

Thank you!!

Still useful in 2013. Saved lots of time for me too. Thanks from the UK.

First of all, Many thanks for sharing this information. I am evaluating a product and I wanted to make sure that the samples are taken in a proper distances..... You saved my time ..I Can do it now ...

Thanks from Canada :)

great help ! thanks a lot!!!

This is great. But if you want greater accuracy without having implement the Vincenty formula from scratch, you can simply adjust your radius according to the the formula at Wikipedia. I did this, and came up with the following formula that works in Google Spreadsheet (and probably Excel too):

=ACOS(COS(RADIANS(90-dLat1*COS(RADIANS(90-dLat2))+SIN(RADIANS(90-dLat1))*SIN(RADIANS(90-dLat2))*COS(RADIANS(dLon1-dLon2))) * SQRT(((6378.135^2*cos(((dLat1+dLat2)/2)*(PI()/180)))^2+(6356.752^2*sin(((dLat1+dLat2)/2)*(PI()/180)))^2)/((6378.135*cos(((dLat1+dLat2)/2)*(PI()/180)))^2+(6356.750*sin(((dLat1+dLat2)/2)*(PI()/180)))^2))Alas, I can't make this more readable with PRE or TT tags, but you can cut and paste it into something with a fixed-width font to try to read it. :)

Very glad I came across this solution. Had not caught the mean vs max radius throwing off my calculations. Thanks!

First off, thank you very much. This helped. Hope I can give back a bit by suggesting a small improvement.

When you go from your initial formula

=ACOS(SIN(Lat1)*SIN(Lat2) +COS(Lat1)*COS(Lat2)*COS(Lon2-Lon1)) *6371

to the one that takes input in degrees

=RadiusEarth*ACOS(COS(RADIANS(90-Lat1)) *COS(RADIANS(90-Lat2)) +SIN(RADIANS(90-Lat1)) *SIN(RADIANS(90-Lat2)) *COS(RADIANS(Long1-Long2)))

you also swap sin and cos in a few places. Not sure why you do this. You're basically just exploiting

COS(RADIANS(90-x) == SIN(RADIANS(x))

So, you could write your formula as

=RadiusEarth*ACOS(SIN(RADIANS(Lat1)) *SIN(RADIANS(Lat2)) +COS(RADIANS(Lat1)) *COS(RADIANS(Lat2)) *COS(RADIANS(Long1-Long2)))

Hope this helps.

You did a great job at making this post very detailed. I want to say thank you! You even supplied the miles and nautical miles needed!

Thank you so so much! This has helped my work so so much!!

C

thank you!! just what i needed to demonstrate to a client, before we implement it in code.

on the first search result.

live long and prosper!829

Mate, you are awesome. I was tearing my hair out trying to make that atan2 thing work and here it is: one formula, in Excel.

The Gods smile on you.

I have a distance calculator but it calc's "nearest" based on sets of l/l inputs so this one did the trick since I needed point to point calculator. Very nice, very easy. As others have said, still relavant in '13.

There is still something wrong in there. If you do the calculation using the same lat and long for lat1 and lat2 and for long1 and long 2, the distance comes out as 6.777km instead of 0km

There is still something wrong in there. Pluug in the same lat and long and instead of 0km, you get 6.777km

Thanks a lot for the formula!

I have adapted it to take input from DDMMSS and converting them into DD.

I checked a few points using some web calculators and seem to be off a few hundred meters. Has anyone experienced this issue?

thank you so much! i'm so glad God brought me to this!

Thanks for your formula

GOD BLESS YOU, GOOD MAN!!!!!

It works very well,

ta.

Thanks a lot for taking the time to create this page, you've saved myself, and clearly a lot of other people, a huge amount of time and effort.

Appreciative from South Africa.

woah! Thats so cool!

Thanks so much!

Party on Wayne!!! Thank you!

Fantastic BlueMM! Saved me so much time I wasn't looking forward deconstructing equations back into excel code. Appreciate the post ...it works perfectly!

Also I noticed someone suggested batchgeo for Geo-coding (Lats and Longs)apparently Google pulled them up for sharing that info so they had to pull it down.

I found this site (http://www.gpsvisualizer.com/geocoder/ ) that allows up to 1000 geo-codes at a time and outputs as a CSV... apply BlueMM's formula and you can do all sorts of fancy things. Thanks so much :)

Wow! You just saved me a lot of work! Thank you simply does not suffice. :o)

Awesome, saved a good while trying to convert some of the other highly ranked posts into excel, alsop uses the formula correctly

Thanks a million!

Greetings from Warsaw, Poland.

hi

I have a spread sheet that has Lat / Lon in three cells each; A1=Lat Degrees; B1 = Lat Minutes; C1 = Lat Seconds (4 decimal places) and D1 = Lon Degrees; E1 = Lon Minutes; F1 = Lon Seconds (4 decimal places).

Now, I will have cells h1 through L1 set the same way. H1 through L1 is my location where A1 through E1 is from a different location.

I want N1 to show range in miles and O1 to show degrees from my location to the other location.

I want to use the "Earth" co-ordinance NAD27.

I tried some formulas I saw on the internet but they did not work. They had something about "time" method.

I use DMS.ssssss only and I do not use meters, which confuses me.

Can some one help?

Contact me at kb8qeu AT gmail DOT com.

Thanks in advance

Ed --- KB8QEU

OH BTW I use excel 4.0 because excel 9 keeps closing automatically. I did have this working on Lotus 123 in the early 90s but can't remember how.

This post continues to help people even though its really old; you have saved a lot of time for a lot of people.

Thank you for your work.

Saved me a couple of hours!

Thanks

thanks dude. still works in 2013!!

Really useful, many many thanks!

Thanks a lot it is of great Help.....was searching a lot and ultimate answer by u......Thnks RIT

I'm gettint #NAME-error. Any tips? Im using excel with OS X.

Fantastic!!!!!!!!!!

Thank you very much. It worked perfect. I set '=ACOS(COS(RADIANS(90-A2)) *COS(RADIANS(90-A3)) +SIN(RADIANS(90-A2)) *SIN(RADIANS(90-A3)) *COS(RADIANS(B2-B3))) *6371

A2 = Lat1

A3 = Lat2

B2 = Lon1

B3 = Lon2

thanks! helped out a lot ! :)

Thank you from Alaska! This saved a lot of time and made my project manageable.

Incredible. Thanks.

Thanks a ton

Thanks a lot! Saved us a lot of pain.

I would really appreciate knowing how I can cite you and your work for my thesis - your equation (as others have said) saved me so much time and effort. Please let me know how to provide due credit! (another biologist tracking life distances)

GPS tracks with holes due to GPS reception loss are my biggest enemy in my quest to GPS tag travel photos.

JGPSTrackEditandExcelwith your formula are my answer to creating missing track points with reasonable time stamps. Thanks for sharing.Immensely helpful. Just saved me a good hour of work in converting PHP code I have which does the same job into Excel. Thank you!

Many thank to you man.... U have saved my time....

Thanks a lot. You surely made my job easy. Thanks.

Brilliant.

Thank you!!! So helpful!!!

Cracking! Thank you for such a neat solution.

thanks a lot friend...you saved my one day of work else had to calculate distance for odd 250 links on google earth...thanks once again

Thank you! You are a life saver. I need to calculate distances between two points for a pricing template and this will do the trick.

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